Area of the track = length of track x breadth of track = 25 x breadth of track = 4500 So, breadth of track = 4500 ÷ 25 = 180 So, perimeter of the track = (25 + 180) x 2 = 410 metres So, speed of the car = (410/10) = 41 m/s Relative speed of the car with respect to the person = 41 + 4 = 45 m/s So, distance between the car and the person, 3 seconds before they cross each other = 45 x 3 = 135 metres
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