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Start learning 50% faster. Sign in nowArea of the track = length of track x breadth of track = 13 x breadth of track = 1300 So, breadth of track = 1300 ÷ 13 = 100 So, perimeter of the track = (13 + 100) x 2 = 226 metres So, speed of the car = (226/10) = 22.6 m/s Relative speed of the car with respect to the person = 22.6 + 5 = 27.6 m/s So, distance between the car and the person, 3 seconds before they cross each other = 27.6 x 3 = 82.8 metres
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