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Area of the track = length of track x breadth of track = 22 x breadth of track = 2200 So, breadth of track = 2200 ÷ 22 = 100 So, perimeter of the track = (22 + 100) x 2 = 244 metres So, speed of the car = (244/20) = 12.2 m/s Relative speed of the car with respect to the person = 12.2 + 4 = 16.2 m/s So, distance between the car and the person, 3 seconds before they cross each other = 16.2 x 3 = 48.6 metres
If Y = -10X and X = -0.1Y, then r is equal to:
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