Area of the circular field = π × radius2 = (22/7) × 14 × 14 = 616 m2 Area of the rectangular piece of land = length × breadth = 20 × 30 = 600 m2 So, difference in area = 616 – 600 = 16 m2
Statements: H @ B, B * E, V © E, W $ V
 Conclusions:     I.W $ E                 II.H @ E               Â...
Statements: C > G > E; E = F; G < HÂ
Conclusions: I) F < GÂ
II) E < CÂ
III) C > H
Statements: L ≤ M = N ≤ O = Q; Z ≥ T > P = Q; L > R = S < V
Conclusions:
I. Z ≥ N
II. V > P
III. R < T
Statement: X < V ≥ A > Y; A ≤ S < W
Conclusions:
 I. X < W
II. S > Y
Statements: Â A % B & G % B; B # L & J; J @ K # S
Conclusions:
I. L @ K
II. A % K
III. S @ B
...Statements:Â Â Â Â Â Â K @ L; M & O, N % L, K $ O
Conclusions:Â Â Â Â Â
I. O @ L
II. M @ LÂ Â Â Â Â Â Â Â Â Â Â Â Â
<...Statement: T < U; W ≤ V = U; I > V; X ≥ U
Conclusion:
I. I > X
II. X ≥ I
Statements: P ≥ S ≥ C ≤ U; N ≥ S < G ; C ≤ M
Conclusion I. P ≥ N II.M < S
...Statements: R ≥ T < U = V > W ≥ X, S < X > Y > Z
Conclusions:
I. U > S
II. T > Z
Statements: I < G = Z = X ≤ A ≤ R < N > D = V
Conclusions:
I. I > D
II. R ≥ G
III. X < V
