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Let the radius of the sphere be 'R' cm. 2304π = (4/3) x π x R3 Or, 1728 = R3 So, R = 12 So, length of edge of the cube = 12 x 2 = 24 cm Required area = 6 x 242 = 3456 cm2
46.2 × 8.4 × 3 + ? = 1200
63- [22-{24 ÷ 3-(9-15 ÷ 5) ÷ 6}]=?
14 × 6 + 9 × 11 = (82 – 3) × ?
(12% of 1250 + 85% of 400) x 10 = ?2
∛21952 × 44 = ? × 14
`sqrt(5476)` + 40% of 1640 = ?`xx` 4 - 2020
654.056 + 28.9015 × 44.851 – 43.129 = ?
212 + 14 × 23 – 28 × 15 = ?
?3 - 25 × 11 = 30 - 15 × 12