The ratio of length to breadth of a rectangle is 5:4, respectively. Perimeter of rectangle is 270 cm. If each side of a square is 25% more than the breadth of rectangle, then find the difference between perimeters of the square and the rectangle.
Let the length and breadth of the rectangle be 5x cm and 4x cm, respectively According to the question, 2 × (5x + 4x) = 270 Or, x = 135/9 = 15 Therefore, each side of the square = 1.25 × 4x = 75 cm Perimeter of the square = 4 × 75 = 300 cm Required difference = 300 – 270 = 30 cm
Statements: H + L & F; F + V $ U; A * U * R
Conclusions:
I. H + U
II. A * F
III. R + L
Statements: J ≥ Q, L > S, L ≥ Q, K = J < N
Conclusion:
I. L > J
II. N > Q
Statements: U < P = I ≤ V < T ≤ R = W > H = Z > O
Conclusions:
I. U < W
II. R > O
Statements: J @ K, K $ L, L & M, M % N
Conclusions: I. K @ M II. N & J
...Statements: R % U, U # V, V @ C, C * F
Conclusions :
I. F $ V
II. C % U
III. R % F
IV. U...
Statements: J < K < M = L, D = E > F, F ≥ G < H = I > J
Conclusions:
I. D > K
II. I < L
III. E > J
Statements : T ≥ G; G > Z < Q ≥ P; P ≥ L < H = E
Conclusions :
I. Q > T
II. L ≤ Q
III. H > G
...Statements: L < M > P ≥ Q; N > O > M
Conclusions:
I. N ≥ Q
II. O > L
III. L = Q
Statement: P < Q; U < R > S; U < T > Q
Conclusion: I. S ≥ P II. P > S
Statement:
N > I ≥ H > O; O ≤ J ≤ K < F; H > P < C; C = R < S;
Conclusion:
I. I > C
II. P < F
III. H < S
