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Let the length of the rectangular field be ‘l’ m Breadth of the rectangular field = (l – 11) m Therefore, perimeter of the rectangular field = 2 ×(l + l – 11) = (4l – 22) m According to the question, 4l – 22 = 560/8 Or, 4l = 70 + 22 Or, l = 92/4 = 23 metres
20% of 240 + 18% of 200 = ?
142 + 233 + ?2 – 301 = 450 + 65
{(123 + ? × 28) – 1254} × (2328 ÷ 97 – 13) = 8195
115 ÷ 23 + 12 × 6 = ? + 16 - 35
1123 + 1452 + 1015 - 2640 = ?
236.23-653.23+696.23=?
(8.6 × 8.6 + 4.8 × 4.8 + 17.2 × 4.8) ÷ (8.62 – 4.82 ) = ? ÷ 19
800 + 900 X (3)-2 - ? = 25 X 60 ÷ 2
(12% of 1250 + 85% of 400) x 10 = ?2