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Let the length and breadth of the rectangular be ‘7x’ metres and ‘8x’ metres, respectively Then, perimeter of the paper = 2 × (length + breadth) = 2 × (7x + 8x) = 30 x metres So, 30x = 60 So, x = (60/30) = 2 So, area of the entire paper = length × breadth = (7 × 2) × (8 × 2) = 14 × 16 = 224 m2 Area of the triangular piece = (1/2) × base × height = (1/2) × 11 × 10 = 55 m2 So, area of the remaining paper = 224 – 55 = 169 m2
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