New Click here to Enroll for SIDBI MSME Expert Class by ex-GM, SBI on Nov 24

    Register

    Question

    There is a rectangular paper, whose length and breadth

    are in the ratio 7:8, respectively and it has a perimeter of 60 metres. If a triangular piece with height of 11 metres and base of 10 metres is cut out from the given paper then find the area (in m2) of the remaining paper.
    A 159 Correct Answer Incorrect Answer
    B 149 Correct Answer Incorrect Answer
    C 139 Correct Answer Incorrect Answer
    D 169 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let the length and breadth of the rectangular be ‘7x’ metres and ‘8x’ metres, respectively Then, perimeter of the paper = 2 × (length + breadth) = 2 × (7x + 8x) = 30 x metres So, 30x = 60 So, x = (60/30) = 2 So, area of the entire paper = length × breadth = (7 × 2) × (8 × 2) = 14 × 16 = 224 m2 Area of the triangular piece = (1/2) × base × height = (1/2) × 11 × 10 = 55 m2 So, area of the remaining paper = 224 – 55 = 169 m2

    Practice Next

    Relevant for Exams: