Two paths of width 9 metres are to be made in the centre of rectangular field such that they are perpendicular to each other. Find the area (in m2) of the field left after making the path if A can complete a round of the field along its boundary in 9.4 seconds while travelling with a speed of 10 m/s and difference between length and breadth of the field is 5 metres.
Let length of the field is ‘l’ metres Breadth of the field = ‘l – 5’ metres So, 2 × (l + l – 5) = 9.4 × 10 = 94 So, 2l – 5 = 47 Or, 2l = 52 So, l = 26 metres And b = 26 – 5 = 21 metres Desired area = 26 × 21 – {26 × 9 + 21 × 9 – 9 × 9} = 546 – 342 = 204 m2
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