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Let length of the field is ‘l’ metres Breadth of the field = ‘l – 5’ metres So, 2 × (l + l – 5) = 9.5 × 8 = 76 So, 2l – 5 = 38 Or, 2l = 43 So, l = 21.5 metres And b = 21.5 – 5 = 16.5 metres Desired area = 21.5 × 16.5 – {21.5 × 4 + 16.5 × 4 – 4 × 4} = 354.75 – 136 = 218.75 m2
[{70 + (40 - 22) ÷ 3} ÷ 4] = ?
1440 ÷ 12 + 540 ÷ √36 + ? = 180 * 3
? = 2640 ÷ {(35% of 1240) – 170}
(5832)1/3 × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
(5832) 2/3 / (104976)3/4X ? = (`sqrt(18)` ` ` ) 5
...`2(1/3)` + `4(1/4)` + `4(2/3)` + `8(7/6)` + ? = `4(3/5)xx4(1/2)`
...(500 × 6 ÷ 10) - (√256 + 8) = ?
42 + 52% of 300 - ?% of 200 = 88
40% of 220 × 15 ÷ 20 = ?
30% of 800 - ?2 = 15