Question
A rectangular piece of copper foil of length 21 cm and
area 924 cm2 is folded along its width to form a cylinder such that there is only one layer of copper foil on any part of the cylinder. What is the volume (in cm3) of the cylinder so formed?Solution
Width of the rectangular piece of copper foil = 924/21 = 44 cm Since the foil is folded along its width to form a cylinder without any double layer, circumference of the cylinder formed = width of the rectangular foil Also, height of the cylinder so formed = length of the rectangular copper foil So, 2 × π × radius = 44 Radius of cylinder = 44 ÷ (2 × 22/7) = (44/44) × 7 = 7 cm So, volume of the cylinder so formed = π × (radius)2 × height = (22/7) × 7 × 7 × 21 = 3234 cm³
What is the simplified value of the given expression?
3(sin² 30° + sin² 60°) + 6sin 45° - (3sec 60° + cot 45°)
If x = r sin A cos B, y = r sin A sin B and z = r cos A, then find x² + y² + z².
- Find the maximum value of (7sin A + 24cos A).
Find the maximum value of 22 sin A + 16 cos A.
- If 4cos²A + 5sin²A = 4.5, then find the value of (sec²A - 1)
- If sin 2a = (7/9), then find the value of (sin a + cos a).
If sec a + tan a = 3/2, find the value of sin a.Â
- Find the maximum value of (12sin A + 16cos A).
If x tan 60° + cos 45° = sec 45° then the value of x2 + 1 is