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Width of the rectangular piece of copper foil = 1078/49 = 22 cm Since the foil is folded along its width to form a cylinder without any double layer, circumference of the cylinder formed = width of the rectangular foil Also, height of the cylinder so formed = length of the rectangular copper foil So, 2 × π × radius = 22 Radius of cylinder = 22 ÷ (2 × 22/7) = (22/44) × 7 = 3.5 cm So, volume of the cylinder so formed = π × (radius)2 × height = (22/7) × 3.5 × 3.5 × 49 = 1886.5 cm³
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If ∆ ABC~∆ FDE such that AB = 9 cm, AC = 11 cm, DF = 16 cm and DE = 12 cm, then the length of BC is: