New Enroll for RBI, PFRDA & NABARD Intro Class! April 18 at 9:15 PM

    Question

    Each side of square ‘A’ is 4 cm less than that of

    square ‘B’. The perimeter of a rectangle is 3 times the difference of the perimeters of the two square. If the length of the rectangle is 15 cm, then find its breadth.
    A 9 cm Correct Answer Incorrect Answer
    B 8 cm Correct Answer Incorrect Answer
    C 10 cm Correct Answer Incorrect Answer
    D 12 cm Correct Answer Incorrect Answer

    Solution

    Let each side of the square ‘A’ be ‘a’ cm Therefore, each side of square ‘B’ = (a + 4) cm Difference between their perimeters = 4(a + 4) – 4a = 16 cm Therefore, perimeter of the rectangle = 3 × 16 = 48 cm Let the breadth of the rectangle be ‘b’ cm According to the question, 2 × (15 + b) = 48 Or, 15 + b = 24 Or, b = 9 cm

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