Each side of square ‘A’ is 4 cm less than that of square ‘B’. The perimeter of a rectangle is 3 times the difference of the perimeters of the two square. If the length of the rectangle is 15 cm, then find its breadth.
Let each side of the square ‘A’ be ‘a’ cm Therefore, each side of square ‘B’ = (a + 4) cm Difference between their perimeters = 4(a + 4) – 4a = 16 cm Therefore, perimeter of the rectangle = 3 × 16 = 48 cm Let the breadth of the rectangle be ‘b’ cm According to the question, 2 × (15 + b) = 48 Or, 15 + b = 24 Or, b = 9 cm
`(601/49)xx(399/81)` ÷ `(29/201)` = ?
30.05% of 250.05 – 15.15% of 99.99 × 2.02 = ?
12.5% of 6400 + (17 × 25) = ?% of 2200+ 125
(? + 6.063.03 ) ÷ 10.08 + 21.89 × 6.97 = 1979.97 ÷ 10.96
In a cyclic quadrilateral ABCD, angle A = 70 degrees and angle B = 100 degrees. What is the measure of angle C?
? = 650.24 + 1124.97 – 14.992
? 2.03 + 121.96 – 55.98 + 129.78% of 59.98 = 399.98
185.92 ÷ 5.98 - (4.002 2 + 114.03 of 5.03 ÷ 18.99 of 6.04 = 5.01 of 2.99 + ? ÷ 12.02
√49 + 6.66% of 1725 + 22² = ?² - √361
(71.78 × 59.88 ÷ 17.92 ÷ 120.22 × 161.72)% of 32 = ?
