Question
Each side of square βAβ is 8 cm less than that of
square βBβ. The perimeter of a rectangle is 6 times the difference of the perimeters of the two square. If the length of the rectangle is 40 cm, then find its breadth.Solution
Let each side of the square βAβ be βaβ cm Therefore, each side of square βBβ = (a + 8) cm Difference between their perimeters = 4(a + 8) β 4a = 32 cm Therefore, perimeter of the rectangle = 6 Γ 32 = 192 cm Let the breadth of the rectangle be βbβ cm According to the question, 2 Γ (40 + b) = 96 Or, 40 + b = 96 Or, b = 56 cm
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