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Let the length of the edges of the two cubes be ‘a’ cm and ‘b’ cm, respectively According to the question, 6a2 + 6b2 = 2328 Or, a2 + b2 = 2328/6 = 388 And, ab = 96 Using the formula, x2 + y2 = (x – y)2 + 2xy 388 = (a – b)2 + 2 × 96 Or, (a – b)2 = 388 – 192 Or, (a – b)2 = 196 Or, a – b = ±14 So desired difference = 14 cm
Which of the following protocols is primarily used to assign IP addresses dynamically to devices on a network?
Which of the following operations is most efficient in a singly linked list compared to an array?
Consider the following Java code that implements encapsulation:
class BankAccount {
private double balance;