Let the length and breadth of the rectangular field be ‘p’ metres and ‘q’ metres respectively Then, according to the question, 2 × (p + q) = 42 Or, (p + q) = 42/2 = 21…… (1) Also p × q = 108 We know, (p + q)2 = p2 + q2 + 2pq Or, p2 + q2 = 212 – 2 × 108 Or, p2 + q2 =441-216=225 So, length of the diagonal of the rectangular field = √(length2 + breadth2) = √(p2 + q2) = √225 = 15metres
?% of 549.83 – 18.05 × 31.96 = 44.94% of 479.84 – 13.98 × 33.13
583.9 + 1519.98 - 445.21 = 1150.011 + ?
15.03% of (619.87 × 7) + (√399.63 × 16.11) ÷ 5 = ?
32.052- 22.03 x 24.199 - 15.18 x 11.04 = ?
36.22 of 249.98% + 299.99 ÷ 30.18 = ?
{14.13 x 28.84 - 39.95% of 420.09 + 128.89} = ?
? = 28.04² ÷ (4.01⁵ + 9.89 × 20.20) + 84.56% of (198.76 × 30.03)
(4913)1/3 × 10.11 × 13.97 ÷ 20.32 = ? + 39.022
509.85 ÷ 15.05 + 210.16 – 18.06 × 5.95 = ?
215.003X4.021 + 11.05 + 71.02 =?