Question
On a rectangular wall of length 22 metres and height 19
metres, there is a window in the shape of triangle surmounted on a square. If the base of triangle and square overlap and length of each side of the square is 10 metres and length of altitude of the triangle is 3 metres, then excluding the window, what is the surface area (in m2) of the wall?Solution
Surface area of the entire wall = length × height = 22 × 19 = 418 m2 Surface area of the window = Sum of surface area of the square part + surface area of the triangular part = 102 + (1/2) × 10 × 3 = 100 + 15 = 115 m2 So, desired surface area = 418 – 115 = 303 m2
What will be the output of the following C code?
#include < stdio.h >
void main ( ) {
  int x = 10, y = 20, *p1 = &x, *p2 = &y;...
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