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According to the question, CSA/TSA = 2/5 ⇒ [2πRh]/[2πR(R + h)] = 2/5 ⇒ h/(R + h) = 2/5 ⇒ 5h = 2R + 2h ⇒ h = (2/3)R .......(1) The volume of a cylinder and the volume of a solid hemisphere are equal. ⇒ πR2h = (2/3)πr3 ⇒ R2 × (2/3)R = (2/3) × (21)3 ⇒ R3 = (21)3 ⇒ R = 21 सेमी ∴ The radius of its base (in cm) is 21 cm.
In a triangle ABC, D, E and F are the mid-points of the sides BD, CA and AB, respectively. BE and DF intersect at X. DE and CF intersect at Y. Find XY = ?
Calculate the area of the square whose perimeter is equal to the perimeter of a rectangle which has length 22 cm & breadth 14 cm .
A frustum of a cone has a lower base radius of 12 cm, an upper base radius of 8 cm, and a height of 15 cm. Find the total surface area of the frustum.
The perimeters of two similar triangles, ∆ PQR and ∆ XYZ are 48 cm and 24 cm respectively. If XY = 12 cm. then PQ is:
If the length of one side of a rhombus is 16cm then find its surface area. (use √ 3 = 1.732)
The perimeter of a rhombus is 60 m and its height is 5 m. Its area is:
