Let the number of steel and copper rods in the storeroom be ‘4k’ and ‘3k’, respectively Let the weight of one steel rod and one copper rod be ‘5y’ kg and ‘7y’ kg, respectively According to the question, 4k × 5y + 3k × 6y = 190 Or, 20ky + 18ky = 190 Or, 38ky = 190 Or, ky = (190/38) = 5 But since we do not have information regarding the exact number of rods in the room, we cannot determine the exact weight of one steel rod.
2, 12, 90, 240, ?, 1260
2, 12, 36, 80, ?, 252
148, ‘?’ , 15 4 , 17 8 , 23 8 , 35 8 , 56 8
2 4 5 19 70...
There are three series given below which are following with the same pattern.
Series I: 1, 12, 38, 193, 1355
Series II: 6, B, C, D, E
...12 10 13 18.5 25.50 ...
14 26 ? 558 4432 44270
...24, 12, 18, ?, 157.5, 708.75
7 26 63 126 215 342
...104 106 110 113 ? 126
