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    Question

    The perimeter of a rectangle is 50% more than perimeter

    of a square of side 25 cm. If the length of rectangle is 100% more than side of square then find the difference between the area of square and the area of rectangle.
    A 425 Correct Answer Incorrect Answer
    B 625 Correct Answer Incorrect Answer
    C 215 Correct Answer Incorrect Answer
    D 450 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Perimeter of the square = 4 x 25 = 100 cm Perimeter of the rectangle = 100 x (150/100) = 150 cm Length of the rectangle = 25 x (200/100) = 50 cm Let the breadth of the rectangle be b cm. => 2 x (50 + b) = 150 => b = 75 тАУ 50 => b = 25 cm Required difference = (25 x 50) - (25 x 25) = 625

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