The perimeter of a rectangle is 100% more than perimeter of a square of side 20 cm. If the length of rectangle is 200% more than side of square then find the difference between the area of square and the area of rectangle.
Perimeter of the square = 4 x 20 = 80 cm Perimeter of the rectangle = 80 x (200/100) = 160 cm Length of the rectangle = 20 x (300/100) = 60 cm Let the breadth of the rectangle be b cm. => 2 x (60 + b) = 160 => b = 80 – 60 => b = 20 cm Required difference = (60 x 20) - (20 x 20) = 800
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If  3  12  108  x   43200
Then, 47% of (x + 72)= ?
8      24       48      144      ?     864
...Find the value of c.
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 31    a     Â...
4 6 ? 31 119 601
...6 , 21, 116, ?, 4674, 33593
6 3.5 2.5 ? 8.5 23.75
...1. In series II, if ‘x’ is the right term, then find which of the following statement(s) are true.
I. x/124 is a factor 6 and 8.
52 25 27 ? 208 1648
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