The perimeter of a rectangle is 110% more than perimeter of a square of side 20 cm. If the length of rectangle is 240% more than side of square then find the difference between the area of square and the area of rectangle.
Perimeter of the square = 4 x 20 = 80 cm Perimeter of the rectangle = 80 x (210/100) = 168 cm Length of the rectangle = 20 x (340/100) = 68 cm Let the breadth of the rectangle be b cm. => 2 x (68 + b) = 168 => b = 84 – 68 => b = 16 cm Required difference = (68 x 16) - (20 x 20) = 688
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