The perimeter of a rectangle is 130% more than perimeter of a square of side 10 cm. If the length of rectangle is 250% more than side of square then find the difference between the area of square and the area of rectangle.
Perimeter of the square = 4 x 10 = 40 cm Perimeter of the rectangle = 40 x (230/100) = 92 cm Length of the rectangle = 10 x (350/100) = 35 cm Let the breadth of the rectangle be b cm. => 2 x (35 + b) = 92 => b = 46 – 35 => b = 11 cm Required difference = (35 x 11) - (10 x 10) = 285
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