Length and breadth of a rectangle are in the ratio 4:5. If the perimeter of the rectangle is 52 cm more than the length of the rectangle, then find the area (in cm2) of the rectangle.
Let the length and breadth of the rectangle be '4x' cm and '5x' cm, respectively. ATQ; 2 × (4x + 5x) = 52 + 5x Or, 18x = 52 + 5x Or, 13x = 52 So, x = 4 So, required area = 4x × 5x = 20 × 42 = 320 cm2
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