Question
The rectangular park has a length-to-breadth ratio of
8:7. Its perimeter exceeds the perimeter of a square-shaped park by 40 meters. The side length of the square park is 4 meters less than the breadth of the rectangular park. Determine the area of the rectangular park.Solution
Let, length and breadth of the rectangular park be ‘8y’ m and ‘7y’ m, respectively. So, 2 × (8y + 7y) – 4 × (7y – 4) = 40 30y – 28y + 16 = 40 2y = 24 y = 12 Therefore, area of rectangular park = 56y2 = 8064 m2
More Mensuration Questions
40.5 ÷ [4/5 of (32 + 18) - 29/2] = ? ÷ 102
(1/2) – (3/5) + 3(1/3) = ? + (5/6)
(350/?) = 23 + 33
25% of 250 + 32% of 200 = ? ÷ √ 16
? = 20% of 1200 + 256
21% of 400 − 150 = ? − 77
172 - 92 + 121 - 74 = ?
24% of 150% of 500 + 140 = ? × 8
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
? = 65% of 40% of (20 × 250) − 200
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