If the perimeter of a rhombus is 2p units and the sum of the diagonals is m units, then find the area of the rhombus?
The perimeter of a rhombus =2p Side =p/2 AC= 2a, BD=2b OB =OD=b In ΔAOB- p²/4 = a² + b² p² =4a²+4b²… (1) m² =(2a+2b) ² m²= 4a²+4b²+8ab m²-8ab =4a²+4b² m²-8ab=p² m²-p²=8abdivided by 4 ¼ (m²-p²) =2ab…. (2) Area 0f rhombus=d₁×d₂/2 = 2a×2b/2 =2ab from equation (2) =m²-p²/4 square unit 
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