If the numerical value of twice the curved surface area of a right circular cylinder is equal to the numerical value of its volume, then what is the numerical value of the diameter of the base of the cylinder?
The curved surface area of the cylinder = 2πrh The volume of the cylinder = πr²h ATQ- 2 × 2πrh = πr²h r = 4cm diameter = 2× 4 =8cm
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