A hemispherical bowl with an internal radius of 15 cm is full of liquid. This liquid will be filled in cylindrical bottles with a radius of 5 cm and a height of 7 cm. How many bottles are required to empty the bowl?
Given – the radius of the hemispherical bowl= 15cm The volume of the hemispherical bowl =2/3 πr3 =2/3×22/7×15×15×15 = (44×225×5)/7 Volume of hemispherical bowl= (44×225×5)/7 Now radius of cylindrical bottles = 5cm. and height =6cm So, the volume of cylindrical bottles = πr²h =22/7 ×25×6 Number of the bottles = (44×225×5)/7)/ (22/7 ×25×6) =15 Number of the bottles = 15
√323.89 × (3.20) ÷ 9.02 =?
599.9 - ? + 64.9 = (5% of 300.012) × 10.032
20.05% of 150.05 – 12.15% of 99.99 × 2.02 = ?
35.05% of 14.87 × (13.02 – ?) + 30.19 = 188.7
14.232 + 19.98% of 629.99 = ? × 6.99
95.001% of 8219.99 - 4/9 % of 5399.98 + 109.99 = ?
(33.95)2 – (25.004)2 + (18.0099)2 – (9.07)2 = ? - (14.990)2
25.22% of (59.9 × 8.01) + 69.97 =?
13³ + 1.3² + 1.03¹ + 1.003 = ?
