Question
The volume of the conical tent is 1232 m3 and
the area of its base is 154m2.Find the length of canvas required to build the tent. If the width of canvas is 5 meters.Solution
Πr2 =154 22/7×r2=154 R = 7cm And now volume of the conical tent =1232 1/3πr2 h=1232 1/3 ×22/7 ×49 ×h = 1232 h= (1232×7×3)/22×49=24m l = √ 576+49 = √ 625 =25cm Area of the canvas required to build the tent = π r l Which will equal to the area of the rectangular canvas. π r l = 2×length of canvas 22/7× 7×25 = 5 × length of canvas length of canvas =22×5 = 110m
(2310.23 ÷ 32.98) + (1008.32 ÷ 23.9) + 1594.11 = ?
? × 32.91 – 847.95 ÷ √16.4 – 13.982 = √24.7 × 24.04
119.98% of 80.02 - 15.12 × 2.02 + 19.95 = ?
25.09 × (√15 + 19.83) = ? of 19.87 ÷ 4.03Â
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
68.98 × 41.03 – (12.33)² + 15.78% of 8398.87 = ? – 40.22
? % of 759.96 + 932.99 = 1237.01
 (3/5) of 3025 + (18² + 12²) = ? + 22.22% of 1125
(70.03 ÷ 3.03 × 12.02) ÷ 35.03 × 20.02 × 8.08 = ? × (9.09 2.02 – 1.01)Â
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
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