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Area of the track = length of track x breadth of track = 45x breadth of track = 6030 So, breadth of track = 6030 ÷ 45 = 134 So, perimeter of the track = (45+ 134) x 2 = 358meters So, speed of the car = (358/16) = 22.3 m/s Relative speed of the car with respect to the person = 22.3+ 5.5 = 27.8 m/s So, distance between the car and the person, 5 seconds before they cross each other = 27.8 x 5= 139 meters
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