Question
 A hollow spherical metallic ball has an external
diameter 8cm and is 1/2cm thick. The volume of the ball (in cm cube) is. type -sscÂSolution
Given- Diameter = 8cm R = 4cm, r = 4-1/2=7/2 cm Volume of the ball = 4 π /3[R3-r3] = (4/3) ×22/7 [64-343/8] = 88/21 [(512-343)/8] = (88/21) ×169/8 =1859/21 =88.52cm 3
1219.98 ÷ 30.48 × 15.12 = ? × 2.16
(1177.99 + 226.99 + 94.923) ÷ 24.97% of 59.989 = ?
447.79 ÷ √(√2400) + 30.94 × 6.07 – 5.08 × 21.96 = ?
7/12 of 539.98 – 23.98 × 9.03 + 77.89 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
[(2/3 of 599.77) + (39.69% of 450.14)] ÷ [(5/8 of 399.79) - √120.91] = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
Find the approximate value of Question mark(?). No need to find the exact value.
(639.78 ÷ 15.96) × 5 + 30.14% of 349.88 – √(224.95) ÷ 5...
(5/9 of 2699.81) + (49.88% of 144.18) - (2/7 of 489.77) = ?
(39.933% of 30.03) - (27.78 `xx` 15.30) = ? - (40 `xx` 38.87)
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