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Let, L = length B = breadth of rectangle ATQ, (L – 4) = (B + 2) L – B = 6 .........(1) Also, LB = (L – 4) (B + 2) LB = LB – 4B + 2L – 8 4B – 2L = – 8 ........(2) After solving (i) and (ii) B=2, L=8 L + B = 10 Now perimeter - Þ 2 (L + B) = 2(10) = 20 cm
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