Question
If the length of certain rectangle is decreased by 4 cm
and breadth is increased by 2 cm, it would result in a square of the same area. What is the perimeter of the original rectangle?Solution
Let, L = length  B = breadth of rectangle ATQ, (L – 4) = (B + 2)  L – B = 6 .........(1) Also, LB = (L – 4) (B + 2) LB = LB – 4B + 2L – 8  4B – 2L = – 8 ........(2) After solving (i) and (ii) B=2, L=8 L + B = 10 Now perimeter - Þ 2 (L + B) = 2(10) = 20 cm
The number of terms in the sequence 20, 25, 30, ….., 160 is:
100Â Â Â Â 221Â Â Â Â 77Â Â Â Â 245Â Â Â Â 50Â Â Â 275
12, 16, 25, 41, 66, ?
If  8      x     6.5    12.25     22.125     36.0625
Then, 20% of 25% of x = ?
...98    148    185    ?     228    238
61, 48, ?, 35, 87, 22
If  7     43    x     1311    5247       15739
Then, x - x/2 + 2 = ?
...5, 11, 32, 65, ?, 389
There are 3 series, you have to find value of a, b, c and then establish relation among a,b,c.
19, 25, 45, a, 553, 2767
1560 760 360 160 6...
8 9 30 155 ? 9837 108218
...