If the length of certain rectangle is decreased by 4 cm and breadth is increased by 2 cm, it would result in a square of the same area. What is the perimeter of the original rectangle?
Let, L = length  B = breadth of rectangle ATQ, (L – 4) = (B + 2)  L – B = 6 .........(1) Also, LB = (L – 4) (B + 2) LB = LB – 4B + 2L – 8  4B – 2L = – 8 ........(2) After solving (i) and (ii) B=2, L=8 L + B = 10 Now perimeter - Þ 2 (L + B) = 2(10) = 20 cm
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If  3  12  108  x   43200
Then, 47% of (x + 72)= ?
8      24       48      144      ?     864
...Find the value of c.
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4 6 ? 31 119 601
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6 3.5 2.5 ? 8.5 23.75
...1. In series II, if ‘x’ is the right term, then find which of the following statement(s) are true.
I. x/124 is a factor 6 and 8.
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