Radius of a cylindrical vessel is 3cm less than breadth of rectangle, while height of cylindrical vessel is equal to length of rectangle, whose area is 540 cm². If ratio between length & breadth of rectangle is 5:3, then find the thickness of 1 disc, if these discs are kept one above another in cylindrical vessel and 10 discs get completely fit in cylindrical vessel. (Let radius of discs equal to radius of cylindrical vessel)?
. Let length & breadth of rectangle be 5x & 3x respectively Given area of rectangle = 540 cm2 5x × 3x = 540 cm2 15x2 = 540 x2 = 36 x = 6 cm Radius of cylindrical vessel = 3 × 6 − 3 = 15 cm Height of cylindrical vessel = 5 × 6 = 30 cm Volume of cylindrical vessel = π × 15 ×15 × 30 = 6750 π cm3 Let thickness of each disc be x cm So, 10 × π × x × 15 × 15 = 6750 π cm3 x = 6750/ (225 x 10) x = 5.88cm.
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