Area of the track = length of track x breadth of track = 48x breadth of track =6000 So, breadth of track = 6000 ÷ 48 = 125 So, perimeter of the track = (48+ 125) x 2 = 346meters So, speed of the car = (346/10) = 34.6 m/s Relative speed of the car with respect to the person = 34.6+ 5.3 = 40 m/s So, distance between the car and the person, 7 seconds before they cross each other = 40 x 7= 280 meters
(75 + 0.25 × 10) × 4 = ?2 - 14
√1369 + √1024 + √841 =(?)2 − 46
What is the value of (152+82) ÷17
Find the HCF of 15x2 + 8x – 12, 3x² + x – 2, 3x² - 2x, 9x² - 12x + 4
14 × 11 + 25 – ? = 21% of 300
36% of 640 – 12.5% of 352 + 25% of 640 = ? – 48% of 432
(72 + 30) ÷ 6 + [{75 ÷ 25) + 6} × 2] = ?
24% of 15% of 500 + 122 = ?2 – (232 ÷ 2)