Let us consider the height of the tower as AB and the distance between the foot of the tower to the point on the ground as BC. In ΔABC, the trigonometric ratio involving AB, BC and ∠ C is tan θ. tan C = AB/BC tan 30° = AB/45 1/√3 = AB/45 AB = 45/√3 = (45 × √3) / (√3 × √3) = (45√3)/3 = 15√3 Height of tower AB = 15×1.73 m. =25.95m
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