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The radius of the sphere is 4/5 times the height of the cylinder. Let the height of the cylinder be 5, then the radius of the sphere = 4. (Radius of the cylinder) ² = 42- (5/2)2 = 16 - 6.25 = 9.75. The radius of the cylinder = √9.75 (But for calculation, let's assume the radius of the cylinder is found accordingly)
In a triangle ABC, D, E and F are the mid-points of the sides BD, CA and AB, respectively. BE and DF intersect at X. DE and CF intersect at Y. Find XY = ?
Calculate the area of the square whose perimeter is equal to the perimeter of a rectangle which has length 22 cm & breadth 14 cm .
A frustum of a cone has a lower base radius of 12 cm, an upper base radius of 8 cm, and a height of 15 cm. Find the total surface area of the frustum.
The perimeters of two similar triangles, ∆ PQR and ∆ XYZ are 48 cm and 24 cm respectively. If XY = 12 cm. then PQ is:
If the length of one side of a rhombus is 16cm then find its surface area. (use √ 3 = 1.732)
The perimeter of a rhombus is 60 m and its height is 5 m. Its area is: