Question
The perimeter of a rectangle of length 2(x + 2) cm and
breadth 2(x + 4) cm is double the perimeter of a square of area 256 cm². Find the area of the rectangle.Solution
Area of square = 256 cm²  Side of square = √256 = 16 cm  Perimeter of square = 16 × 4 = 64 cm  So, perimeter of rectangle = 2 × 64 = 128 cm  ⇒ 2(2(x + 2) + 2(x + 4)) = 128  ⇒ 4x + 12 = 64  ⇒ 4x = 52  ⇒ x = 13  So, length of rectangle = 2(13 + 2) = 30 cm  And, breadth of rectangle = 2(13 + 4) = 34 cm  Therefore, area of rectangle = 30 × 34 = 1020 cm²
3720 3842 ? 4092 4220 4350
...2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 19Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 70...
Complete the series: 5, 20, 24, 6, 2, 8,?
12    16    43    ?       184    220
...2401 2402 1203 ? 105 26
...9 10 6 15 -1 ?
...D irection: Which of the following will replace ‘?’ in the following series
300, 300, 301, 303, ‘?’, 324, 364
...If 4 10 16 26 x 50
Then find the value of (x² - 1) + ( x² + 1).
...4Â Â Â Â Â Â Â Â Â 5.5Â Â Â Â Â Â Â Â Â Â Â 19 .5Â Â Â Â Â Â Â Â Â Â Â Â Â 98.5Â Â Â Â Â Â Â Â Â Â Â Â Â Â 694Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 6251.5...
The question below is based on the given series I. The series I satisfy a certain pattern, follow the same pattern in series II and answer the questions...
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