Question
The length of the diagonal of a rectangle is 26 cm, and
one side is 10 cm. The area of the rectangle is:Solution
According to the given information, Length of diagonal of the rectangle of side length 'a' and 'b' = √(a² + b²) = 26 cm One side length (Let's assume it's 'a') = 10 cm √(10² + b²) = 26 On squaring both sides, we get, 102 + b² = 676  b2 = 676-100 b = √576 = 24 cm  Area of given rectangle = a x b = 10 x 24 = 240 sq cm
Which of the given trigonometric identities is incorrect ?
1. tan2 θ = sec2 θ - 1B. cosec2 θ = 1 + cot
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
? + 157.99 – 101.01 = 25.01 × 5.98
8.15 of 124.95 ÷ 40.13 + 249.84 X 14.18 - √325 X 149.87 = ? X 10.85
(1440.13 ÷ 31.77) × (√168.69 + 16) - (24.87% of 719.99) = ?
499.98% of (√440.8 + 12.922 ) - 12.02 of 4.82 = ? of 9.82 + 9.98% of 999.94
(363.89% of 224.98 – 319.86% of 134.94) ÷ ? = √(134.88 ÷ 15.25)
16.22 × 12.99 + 142.15 = ?
(98.999)2 - (9.9)2 - (14.9)2 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
