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ATQ, Let, length and breadth of cuboidal box be 11m cm and 8m cm, respectively. So, 2 × (11m + 8) × 80 = 6.08 × 10000 19m = 380, m = 20 Volume of cuboidal box = (220 × 160 × 80) cm3 Volume of each cubical box = (20 × 20 × 20) cm3 Required cost = {(220 × 160 × 80)/8000}× 12 = Rs.4224
1199.98 ÷ 40.48 × 20.12 = ? × 3.16
85% of 1740 + 30² = ? + 1575 ÷ 15
12.023 + 32.05 × 16.08 – 84.04% of 2400 = 56.06% of ?
386.99 + 397.99 + ? - 232.02 = 35.02 × 31.99
15.2 x 1.5 + 258.88+ ? = 398.12 + 15.9
(√899.69 + 49.83% of 640.24)² - (7/8 of 479.79) = ?
√440.98 + (17.95% of 249.96 – 12% of 99.99) + (7.12)2 = ?
25.05% of 220.05 – 10.15% of 119.99 × 2.02 = ?
?2 = 159.97% of 65.004 + 319.98 ÷ 15.99 - 24