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ATQ, Area of the field = 5000/10 = 500 cm² So, (x + 6)(x – 3) = 500 Or, x² + 3x – 500 = 0 Or, x² + 25x – 20x – 500 = 0 Or, x(x + 25) – 20(x + 25) = 0 Or, (x + 25)(x – 20) = 0 So, x = 20 Perimeter of the field = 2 × {(20 + 6) + (20 – 3)} = 86 metres Desired cost = 86 × 12 = Rs. 1032
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