Question
Perimeter of a rectangle is 60% more than that of a
square of side 20 cm. If the difference between the length and breadth of the rectangle is 10 cm, respectively, then find the length of the rectangle.Solution
ATQ, Perimeter of square = 20 X 4 = 80 cm Perimeter of rectangle = 1.60 X 80 = 128 cm Let the breadth of rectangle be 'x' cm So, length of rectangle = 'x + 10' cm ATQ, 2(x + x + 10) = 128 Or, 2x + 10 = 64 Or, 2x = 54 So, 'x' = 27 Length of rectangle = 'x + 10' = 27 + 10 = 37 cm
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