Get Started with ixamBee
Start learning 50% faster. Sign in now
ATQ, Let, breadth of the field be ‘x’ m. So, the length of the field = ‘1.2x’ m. Therefore, 2 × (x + 1.2x) = 300 2.4x = 150 x = 62.5 Therefore, the breadth of the field = x = 62.5 metres. Length of the field = 1.2x = 75 metres. So, the area of the path = (80 × 67.5) – (62.5 × 75) = 5400 – 4687.5 = 712.5 m². Required cost = 712.5 × 20 = Rs. 14250.
If secθ + tanθ = 3+√10, then the value of sinθ+cosθ is
If sec(2A + B) = 2 and cos(A + B) = (1/√2) , find the value of {sec 2B + tan (A + B) } given that 0o < A, B < 90o
Two points P and Q are at the distance of x and y (where y > x) respectively from the base of a building and on a straight line. If the angles of elevat...
If P, Q, R, S are the vertex of a cyclic quadrilateral. Find the value of
`1/sec p` +`1/sec q` +`1/sec r` +`1/sec s`
...From a point on the ground, the angle of elevation of the top of a building is 45°. After walking 10 meters towards the building, the angle of elevatio...
Find the simplified value of the following expression if a = 30o
[(sin2a + cos2a} ÷ seca × sina ÷ cosa]
...Calculate the value of sec75o
If sin (2x + 50) o = cos (2y - 50) o, such that, 0o < x + y < 90o, then find the value of tan(x + y) .
ABC is an isosceles triangle where AB = AC which is circumscribed about a circle. If P is the point where the circle touches the side BC, then which of ...
If tan θ + cot θ = 2 where 0 < θ < 90 ; find the value of tan30 θ + cot 29 θ.
