A path of width 2.5 m is made outside and around a rectangular field of perimeter 300 m. If the length of the field is 20% more than its breadth, then find the cost of paving the path at Rs. 20 per m².
ATQ, Let, breadth of the field be ‘x’ m. So, the length of the field = ‘1.2x’ m. Therefore, 2 × (x + 1.2x) = 300 2.4x = 150 x = 62.5 Therefore, the breadth of the field = x = 62.5 metres. Length of the field = 1.2x = 75 metres. So, the area of the path = (80 × 67.5) – (62.5 × 75) = 5400 – 4687.5 = 712.5 m². Required cost = 712.5 × 20 = Rs. 14250.
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