Question
The area of the rectangular field is 540 m² and its
perimeter is 94 m. Find how much percent (approximately) less the breadth of the field is compared to the length of the field?Solution
ATQ, Let the length and the breadth of the rectangular field be ‘l’ meter and ‘b’ meter, respectively. So, the area of the rectangular field = l × b = 540 l = 540/b Perimeter of the rectangular field = 2(l + b) = 94 l + b = 47 540/b + b = 47 540 + b² = 47b b² – 47b + 540 = 0 b² – 30b – 17b + 540 = 0 b(b – 30) – 17(b – 30) = 0 (b – 17)(b – 30) = 0 b = 30, 17 b = 17 m and l = 30 m as length is greater than breadth So, the desired percentage = {(30 – 17)/30} × 100 = 43.33% or 43%
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