Question
A solid metal cylinder of 12 cm height and 7 cm radius
is melted and recast into two cones in the proportion of 1:2 (volume), keeping the height 12 cm. What would be the percentage change in the flat surface area before and after [use π =22/7]?Solution
Volume of Cylinder = πr²h = π × 72 × 12 = 588π Now, the solid metal cylinder is re-cast into two cones in the proportion 1: 2 i.e. the volumes of cone 1 and cone 2 is 196 π and 392 π respectively. So, flat Surface area of cylinder before melting = 2πr² = 2 × 72 = 98π  Volume of cone 1 =1/3 πr1²h= 196π  r12 = (196×3/ 12) = 49 Volume of cone 2 = 1/3πr2²h = 392π  r22 = 392×3 /12 = 98 Flat surface area of cones = π (r12 + r22) = π (49 + 98) = 147π  Percentage change in surface area = (147-98π) /98π × 100 = 1/2 × 100 = 50%
How is the available surplus calculated for the accounting year commencing after the commencement of this Code and for every subsequent accounting year ...
A Partner of an Unregistered Firm cannot sue the Firm or any other Partner of the Firm to enforce a right:
What is the time period within which the mount of the dividend, including interim dividend, shall be deposited in a scheduled bank in a separate accoun...
Which one of the following sections of the Indian Penal Code relates with punishment for counterfeiting currency notes or Bank notes?Â
Section 19 of the Court Fee Act 1870 relates to:Â
Which of the following is not required for criminal intimidation under Section 351?
Article 18 of Constitution of India is related to
The Governor shall address ________________ at the commencement of first session of each year:
Which of the following are punishments under Section 4 of the Bharatiya Nyaya Sanhita?
The words and expressions used but not defined under the Competition Act, 2002 shall have the same meanings respectively assigned to them in ___________...
Relevant for Exams:
