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△ ABC with P on AB such that PB: AP = 3: 4. PQ || AC. AR ⊥ PC and QS ⊥ PC. QS = 9 cm. Proportional Segments: Given – PB: AP= 3: 4, let PB = 3k and AP = 4k. Therefore, AB = PB + AP=3k =4k = 7k. Similar Triangles: Since PQ || AC, triangles △ APQ and △ APC are similar. This implies the ratio of their corresponding sides is. PB/AB=3/7 Area of △PBQ/△ABC =9/49 Ratio of △APC and △QPC- =½ ×PC×AR: ½×PC×QS =AR: QS △APC/△QPC =AR/QS … (1) Area of △PBQ=9 and △QPC =12 Now Area of △APC =△ABC –(△PBQ+△QPC) =49-(9+12) =28. From Eq-(1) 28/12 =AR/9 AR =21cm.
Statements: V ≤R = W ≥ Q, U = T ≥ S < X, U < Q
Conclusions: I. V < Q II. Q > X
Statements: Q © E, S % C, E $ S, C @ A
Conclusions:
I. A © C
II. S % A
III. C © Q
Statements: L # W, W % V, V $ H, H # T
Conclusions : I. V @ T II. H & W III .V # T
...Which of the following symbols should be placed in the blank spaces respectively (in the same order from left to right) in order to complete the given e...
Which of the following is true in the given expression?
G < H ≤ I, V ≥ W = G, R ≤ I = A
In which of these expression ‘X > T’ is definitely True?
Statements: Q ≥ R > U; R ≤ S; U ≥ B
Conclusions: I. B < R II. B ≤ Q
Statement: Z > F ≥ O; Z ≤ G = P; Q > F
Conclusion: I. P > O II. Q > G
Statements: Q > S ≥ R = T; U < V = W < X = Y ≤ T
Conclusions:
I. R > U
II. T < U
III. U ≥ R
Statement: T > U ≥ V; T ≤ W = X; I > U
Conclusion: I. U < X II. I > T
