Πr2 = 616 22/7×r2= 616 R = 14 cm And now the volume of the conical tent = 4928 1/3πr2 h= 4928 1/3 ×22/7 × 196 ×h = 4928 h= ( 4928 ×7×3)/22× 196 =24m l = √ 576+196 = √ 772 =2 7.7 cm The area of the canvas required to build the tent = πr l Which will equal the area of the rectangular canvas. π r l = 2×length of canvas 22/7× 7× 27.7 = 2 × length of canvas length of canvas =11×2 7.7 = 304.7 m
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