Question
A right circular cylinder of height 15cm is covered by a
rectangular tin foil of size 15cm Γ24cm. the volume of the cylinder is.Solution
if tin foil covered then the curved surface area of cylinder is equal to the area of tin foil. Curved surface area = 15 Γ24 H = 15cm Volume = (C.S.A)2 /4 Ο h = (15Γ22Γ15 Γ22Γ7) /4Γ22Γ15 = (15Γ22Γ7)/4 = 77Γ15/2 =577.5cm3
More Mensuration Questions
β [? x 11 + (β 1296)] = 16
? = 6.25% of 240 + 252 + 172 β 16 Γ 17
436 × 794 – 68210 =? + 85730
?/4 ÷ 9/? = 15% of 800 + `1(2/3)` × `1(1/5)` × 1/2
16 Γ 14 + 30 Γ 21 = 14 Γ ?
60% of 250 + 14 Γ 10 - 210 = ?
What will come in the place of question mark (?) in the given expression?
30% of 520 + 16% of 1500 = ? + 244
33 × 5 - ?% of 250 = 62 - 6
140% of 9/8 of ? = 108% of 2800
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