Πr2 =198 22/7×r2=198 r2 = 63cm r=7.95=8(approx.) And now the volume of the conical tent =980 1/3πr2 h=980 1/3 ×22/7 ×63 ×h = 980 h= (980×7×3)/22×63 h=20580/1386=14.8m l = √219.04+63= √282.04 =16.7cm The area of the canvas required to build the tent = πr l Which will equal the area of the rectangular canvas. π r l = 4×length of canvas 22/7× 8×16.7 = 4 × length of canvas length of canvas =3.14×2×16.7 = 104.8m
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