Two equal circles are drawn on a square in such a way that opposite side of the square forms the diameter of each circle. If the remaining area of the square is 42 cm2, what is the measurement (in cm) of the diameter of each circle?
Here, AB and CD are diameters. Let AB = 2x cm Radius of circle = x cm Area of remaining part of the square = (2x) ²-Пх² = 4x²-Пх² According to question, 4x2-Пх2=42 x² [4-22/7] = 42 x2 x 6/7 = 42 x2=49 x = 7cm Diameter of circle = 7×2 = 14 cm 
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