Here, AB and CD are diameters. Let AB = 2x cm Radius of circle = x cm Area of remaining part of the square = (2x) ²-Пх² = 4x²-Пх² According to question, 4x2-Пх2=42 x² [4-22/7] = 42 x2 x 6/7 = 42 x2=49 x = 7cm Diameter of circle = 7×2 = 14 cm 
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