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Hence, the radius of the inner part = 8-1 = 7 cm The volume of the metal used for the shell should equal the difference between the volume of the outer and inner parts. Thus, the volume of the metal used for the shell =4/3 π (83 – 73) = 4/3 ×22/7×169 =14872/21 cm³ =708.19 cm3 The volume of the metal used for the shell is 708.19 cm³
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